(sec8A+sec4A-2)/(sec8A-sec4A) is equal t...

`(sec8A+sec4A-2)/(sec8A-sec4A)` is equal to (A) `(tan 6A)/(tan 10A)` (B) `(cos 10A)/(cos 6A)` (C) `(sin 10A)/(sin 6A)` (D) `(tan10A)/(tan 6A)`

Similar Questions

Explore conceptually related problems

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

(tan A + sec A-1) / (tan A-sec A + 1) = (1 + sin A) / (cos A)

Prove that (i) (sec 8A -1)/(sec 4A -1) =(tan 8A)/(tan 2A) (ii) (cos A+ sin A)/(cos A - sin A)-(cos A-sin A)/(cos A+sin A)=2 tan 2A

Prove that : (tan A + sec A - 1)/ (tan A - sec A + 1) = (1 + sin A)/ (cos A)

(cos ecA-sin A) (sec A-cos A) sec ^ (2) A = tan A

(sec A+tan A)(1-sin A)=sec A(b)sin A(c)cos ecA(d)cos A

Prove: (sec A-tan A)/(sec A+tan A)=(cos^(2)A)/((1+sin A)^(2))