[" Find the magnetic "],[" fleld (in "10^(-7)" T ) due to "],[2" wires as shown at "],[(0,0,1)" m."],[" y-wire in xy plane "],[(160^(@))/(i=2A)'x]

Find the Magnetic field (in 10^(-7)T ) due to long wires as shown at (0,0,1)m

Find the magnetic field (in 10-7 T) due to 2 long wires as shown at (0,0,1) m. у (wire in xy plane) 60° i=2A z

In the previous example find the mass of the wire if the magnetic field is equal to the earth magnetic field (4 xx 10^(-5) T) , current in the wire is 5 A and length of the wire is 1m. The wire remains suspended in mid air in equilibrium. (take g = 10 m//s^(2) )

A long thin wire is placed along the y-axis (just outside) of a frame of refernce. There exists a uniform magnetic field of 10^(-6) T along the x-axis. Calculate the magnetic field at the points (0,0,2m),(0,2m,0) and (2m,0,0) when the wire carries 10A current. Revise the calculation for a thick wire.

Wire 1 in Fig. is oriented along the y-axis and carries a steady current I_1 . A rectangular loop located to right of the wire and in the x-y plane carries a current I_2 . Find the magnetic force exerted by wire (1) on the top of wire (2) of length b in the loop, labeled "wire (2)" in the figure.

There are two infinite parallel current carrying wires in vertical plane. Lower wire is fixed and upper wire is having a linear mass density lambda . Two wires are carrying currents I_(1) and I_(2) . Now upper wire is placed in a magnetic field produced by lower wire. Magnetic field due to lower wire at the location of upper wire is (mu_(0)I)/(2pid) , where I_(1) current lower wire, d separation between wires. Force on any small portion of upper wire having length dl is dF=(mu_(0)I_(1)I_(2)dl)/(2pid), where I_(2) current in the upper wire. If directions of current in the wires is appropriate then upper wire can be in equilibrium if its weight is balanced by magnetic force. Now answer the following questions. Equilibrium separation between the two wires is

There are two infinite parallel current carrying wires in vertical plane. Lower wire is fixed and upper wire is having a linear mass density lambda . Two wires are carrying currents I_(1) and I_(2) . Now upper wire is placed in a magnetic field produced by lower wire. Magnetic field due to lower wire at the location of upper wire is (mu_(0)I)/(2pid) , where I_(1) current lower wire, d separation between wires. Force on any small portion of upper wire having length dl is dF=(mu_(0)I_(1)I_(2)dl)/(2pid), where I_(2) current in the upper wire. If directions of current in the wires is appropriate then upper wire can be in equilibrium if its weight is balanced by magnetic force. Now answer the following questions. The upper wire can be in equilibrium if