[" The acceleration of a particle which is depend on time is given by following function "],[a=2t+1" and at time "t=0,x=1m" and "u_(t)=2m/s." Then find out displacement of the "],[" particle from "t=0" to "t=3" sec."]

The acceleration of a particle which is depend on time is given by following function a = 2t + 1 and at time t = 0, x = 1m and ui = 2m/s. Then find out displacement of the particle at t = 3 sec.

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The acceleration a of alpha of a particle depends on displacements covered in a time t as a= S + 5 . It is given that initially S=0 m and v=5m//s . Then

The magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be –

[" Velocity of a particle moving along "x" -axis "],[" as a function of time is given as "v=(4-],[t^(2))m/s," where "t" is time in second.The "],[" displacement of particle during "t=0s" to "t],[=1s" is "]

The accelerating of particle varies with time as shown (a)Find an expression for velocity in terms of t. (b)Calculate the displacement of the particle in the interval from t=2s "to" t4s .Assume that v=0 at t=0

A starts from rest, with uniform acceleration a. The acceleration of the body as function of time t is given by the equation a = pt, where p is a constant, then the displacement of the particle in the time interval t = 0 to t=t_(1) will be

A starts from rest, with uniform acceleration a. The acceleration of the body as function of time t is given by the equation a = pt, where p is a constant, then the displacement of the particle in the time interval t = 0 to t=t_(1) will be

The displacement of a particle at time t is given by s= 2 t^3 - 5 t^2 + 4t -3. Find the time when the acceleration is 14 ft/ sec^2 , find the velocity and the displacement at that time.