[" 11in a moving coil gavanometer a currentl in its coll produces a deflection then "],[" bPT10Ns "],[" 0."100],[" b."1000^(2)],[" a."10sqrt(theta)],[" d."1times tan theta]

A moving coil galvanometer shows a deflection of 50^@ for a current of 0.3 mA. What current will produce a deflection of 40^@ ?

The resistance of a moving coil galvanometer is 99Omega and the current for its full scale deflection is 100muA . To convert the galvanometer into an ammeter to read a maximum current of 10 mA, what should be the resistance to be connected in parallel with it?

The resistance of a moving coil galvanometer is 500Omega and the current required for its maximum deflection is 10muA . To convert the galvanometer into a voltmeter to read a maximum voltage of 100 mV, what should be the resistance to be connected in series with it?

In moving coil galvnometer a current f 2A for radial magnetic field of 4xx 10^(-3) Wb/m^(2) produces some deflection. FI the field is doubled by keeping all other quantities same, the current for the same deflection will be

A moving coil galvanometer needs a current of 100muA for a full scale deflecion of 50 divisions. If the resistance of the galvanometer is 1000 Omega, then its current senstivity is

A moving coil galvanometer coil has a coil of area A, number of turns N. The radial magnetic field present is B. the moment of inertia of the coil is I about its rotation axis. The torque is applied by the magnetic field on the coil of the galvanometer when current I_(0) passes through it and produces a deflection of pi//2 of the pointer. Then answer the following questions based on the paragraph. If the charge Q is passed almost instantaneosly through the coil, the angular velocity of the coil, immediately after this is

A moving coil galvanometer of resistance 10 ohm produces full scale deflection, when a current of 25 mA is passed through it. How will you convert the galvanometer into an ammeter reading upto 20 A.

A moving coil galvanometer of resistance 10 ohm produces full scale deflection, when a current of 25 mA is passed through it. How will your convert the galvanometer into a voltmeter reading upto 120 V

A moving coil galvanometer coil has a coil of area A, number of turns N. The radial magnetic field present is B. the moment of inertia of the coil is I about its rotation axis. The torque is applied by the magnetic field on the coil of the galvanometer when current I_(0) passes through it and produces a deflection of pi//2 of the pointer. Then answer the following questions based on the paragraph. Then the value of torsionl constant of the spring is