10x^(2)-27x+5=6

Solve for x: (i) 10x^(2)-27x+5=0 (ii) pqx^(2)-(p^(2)+q^(2))x+pq=0

Solve for x: (i) 10x^(2)-27x+5=0 (ii) pqx^(2)-(p^(2)+q^(2))x+pq=0

Solve for x: (i) 10x^(2)-27x+5=0 (ii) pqx^(2)-(p^(2)+q^(2))x+pq=0

Verify that 5, -2 and 1/3 are the zeros of the cubic polynomial p(x) = 3x^(3) - 10x^(2) - 27x+10 and verify the relation between its zeros and coefficients.

If two roots of 2x^(3)-15x^(2)+27x-10=0 are in the ratio 2:5 then the roots are

Solve: (i) 27x^(2)-10x+1=0 . (ii) 21x^(2)-28x+10=0 .

F(x)=x^(4)-3x^(3)-7x^(2)-10x-25G(x)=x^(4)-4x^(3)+x^(2)-27x-15 Fidn the number of values o x for which f(x)=g(x)=0

The HCF of (6x^(4)-13x^(3)+6x^(2)) and (8x^(4)-36x^(3)+54x^(2)-27x) is

Solve the following : 10 x^2 - 27 x +5 = 0

y=x^(4)-6x^(3)+13x^(2)-10x +5 at (0,5).