Delta H=30kJmol^(-1),Delta S=75J/k/mol." Find boiling temperature at "1" atm."

DeltaH=30kJmol^(-1), DeltaS=75J//K//mol. "find boiling temperature at" 1atm:

DeltaH=30kJmol^(-1), DeltaS=75J//K//mol. "find boiling temperature at" 1atm:

Steam undergoes decomposition at high temperature as per the reaction : H_(2)O(g)to H_(2)(g)+(1)/(2)O_(2)(g) Delta H^(@)=200kJmol^(-1)Delta S^(@)=40JK^(-1)mol^(-1) The temperature at which equilibrium constant is unity is :

Delta_(vap)H = 30 kJ mol^(-1) and Delta_(vap)S = 75Jmol^(-1)K^(-1) . Find the temperature of vapour, at 1 atm.

For the reaction Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g) the value of Delta H=30.56 KJ mol^(_1) and Delta S = 66 JK^(-1)mol^(-1) . The temperature at which the free energy change for the reaction will be zero is :-

For the reaction Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g) the value of Delta H=30.56 KJ mol^(_1) and Delta S = 66 JK^(-1)mol^(-1) . The temperature at which the free energy change for the reaction will be zero is :-

For the reaction Ag_(2)O(s)rarr 2Ag(s)+1//2O_(2)(g) the value of Delta H=30.56 KJ mol^(_1) and Delta S = 66 JK^(-1)mol^(-1) . The temperature at which the free energy change for the reaction will be zero is :-

Delta_(vap)H = 30 kJ mol^(-1) and Delta_(vap)S = 75 mol^(-1)K^(-1) . Find the temperature of vapour, at 1 atm.

At 1 atm pressure, DeltaS=75JK^(-1)mol^(-1),DeltaH=30kJ" "mol^(-1) , the temperature of the reaction at equilibrium is