A particle moves under the law `s=t^(3)-4t^(2)-5t.` If its acceleration is `4" units/sec"^(2)`, then its displacement is

A particle moves under the law s=t^(3)-4t^(2)-5t. If its acceleration is 4" units/sec^(2), then its velocity is

If S=4 t^(3)-3t^(2)+2 , then acceleration is 42 "units" // sec ^(2) at the time t=

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its acceleration is 14" ft/sec"^(2) after to,e

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its displacement when acceleration is 14" ft/sec"^(2) , is

If the displacement of a particle is given by s=2t^(3)-5t^(2)+4t-3 , then its velocity when acceleration is 14" ft/sec"^(2) , is

A particle moves according to the law x=t^(3)-6t^(2)+9t+5 . The displacement of the particle at the time when its acceleration is zero, is

The displacement of a particle at time t is given by s= 2t^(3) -5t^(2)+ 4t-3 . The time when the acceleration is 14ft/ sec^(2) is

A particle moves along a straight line according to the law s=t^3-3t^2+5t . Find its velocity and acceleration at the end of 1 sec.

A particle moves according to the law s= t^3-6t^2+9t +5 . The displacement of the particle at the time when its acceleration is zero is........ A) 9 B) -7 C) 7 D) 0