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If int0^ooe^(-x^2) dx=(sqrtpi)/2 , then...

If `int_0^ooe^(-x^2) dx=(sqrtpi)/2 `, then `int_0^ooe^(-ax^2) dx ` where ` a gt 0` is: (A) `(sqrtpi)/2` (B) `(sqrtpi)/(2a)` (C) `2(sqrtpi)/a` (D) `1/2(sqrt(pi/a))`

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