the value of `2/(1!)+ (2+4)/(2!) + (2+4+6)/(3!) +..................` is

The value of 1- 1/2(3/4) + 1/3(3/4)^(2) -1/4(3/4)^(3) + ... is:

Find the value of 5(1)/(2) - [3(1)/(4) + 6 - 4 div 2]

The value of 2/3+3/4+1/2+1/4 is

" 4.Find the value of "(6)^(1/2)x(6)^(3/2)

Without expanding, find the value of: (2x - 1)^4 + 4(2x - 1)^3 (3 - 2x) + 6(2x - 1)^2 (3 - 2x)^2 + 4(2x - 1) (3 - 2x)^3 + (3 - 2x)^4