Home
Class 9
MATHS
BE and CF are two equal altitudes of a ...

BE and CF are two equal altitudes of a triangle ABC. Using RHS congruence rule, prove that the triangle ABC is isosceles.

Text Solution

AI Generated Solution

To prove that triangle ABC is isosceles using the RHS (Right angle-Hypotenuse-Side) congruence rule, we will follow these steps: ### Step 1: Identify the Right Triangles We have triangle ABC with altitudes BE and CF from points B and C to side AC. We will consider the two right triangles: - Triangle BEC (where BE is the altitude) - Triangle CFB (where CF is the altitude) ### Step 2: Establish Right Angles ...
Promotional Banner

Topper's Solved these Questions

  • TRIANGLES

    NCERT|Exercise Solved Examples|9 Videos
  • TRIANGLES

    NCERT|Exercise EXERCISE 7.4|6 Videos
  • SURFACE AREAS AND VOLUMES

    NCERT|Exercise EXERCISE 13.8|10 Videos

Similar Questions

Explore conceptually related problems

In a triangle ABC, if angleA=angleB+angleC , the prove that triangle ABC is a right triangle.

If the altitudes from two vertices of a triangle to the opposite sides are equal,prove that the triangle is isosceles.

If the altitudes from two vertices of a triangle to the opposite sides are equal,prove that the triangle is isosceles.

If in a Delta ABC, c(a+b) cos B//2 = b(a+c) cos C//2 , prove that the triangle is isosceles.

In triangle ABC , if cosA+sinA-(2)/(cosB+sinB)=0 then prove that triangle is isosceles right angled.

AD and BE are respectively altitudes of an isosceles triangle ABC with AC=BC . Prove that AE=BD

If AD,BE,CF are the altitudes of triangle ABC whose ortho centre is H then C is ortho centre of

In a Delta ABC if (a+b)cos((B)/(2))=b(a+c)cos((C)/(2)) then prove that the triangle ABC is isosceles.