`cosx+sinx=1`

Show that (1-cosx)/sinx = sinx/(1+cosx)

Determine the maximum value of |[cosx sinx], [-sinx cosx-1]| .

If y=|[sinx, cosx, sinx],[cosx,-sinx,cosx],[x,1,1]| then find (dy)/(dx)

Prove that (1+sinx-cosx)/(1+sinx+cosx) +(1+sinx+cosx)/(1+sinx-cosx) =2 cosec x

Prove that (1+sinx-cosx)/(1+sinx+cosx) +(1+sinx+cosx)/(1+sinx-cosx) =2 cosec x

If Delta(x)=|(1,cosx,1-cosx),(1+sinx,cosx,1+sinx-cosx),(sinx, sinx ,1)| then int_0^(pi//2)Delta(x) dx is equal to :

Solve sinx+cosx=1+sinx.cosx

Solve (sinx)/(1+cosx)+(1+cosx)/(sinx)

If y=(sinx)/(1+(cosx)/(1+(sinx)/(1+(cosx)/(1+ tooo)))),p rov et h a t(dy)/(dx)=((1+y)cosx+ysinx)/(1+2y+cosx-sinx)