" If "sec A+tan A=x," then "sec A=

If sec theta+tan theta=x then sec theta=

If sec theta+tan theta=x, then sec theta=(a)(x^(2)+1)/(x) (b) (x^(2)+1)/(2x)(c)(x^(2)-1)/(2x) (d) (x^(2)-1)/(x)

If x sec alpha+y tan alpha=x sec beta+y tan beta=a , then sec alpha*sec beta=

If sec theta + tan theta = x , then sec theta =

(sec x sec y + tan x tan y) ^ (2) - (sec x tan y + tan x sec y) ^ (2) = 1 Prove it

The curve y=sec x tan x+2tan x-sec x and the line y=2 intersect in

If x in [0,2pi] and |sec x+ tan x|=|sec x|+|tan x| , then x lies in the interval

Evaluate : int (" sec x + tan x")/(" sec x- tan x") " dx "

Evaluate : int (" sec x + tan x")/(" sec x- tan x") " dx "