A curve passing through the point (1,2) has the property that the perpendicular distance of the origin from normal at any point P of the curve is equal to the distance of P from the x-axis is a circle with radius.

Find the equation of a curve passing through the point (1.1) if the perpendicular distance of the origin from the normal at any point P(x,y) of the curve is equal to the distance of P from the x-axis.

A curve y=f(x) has the property that the perpendicular distance of the origin from the normal at any point P of the curve is equal to the distance of the point P from the x-axis. Then the differential equation of the curve

The perpendicular distance of the point P(7,5) from the x-axis is

The perpendicular distance of the point P(3,4) from the Y-axis is

The perpendicular distance of the point P(4,2) from the x-axis is:

The perpendicular distance of the point p(-7,2) from y-axis is

The perpendicular distance of the point p(- 4, -3) from x-axis is

Let C be a curve y=f(x) passing through M(-sqrt(3),1) such that the y-intercept of the normal at any point P(x,y) on the curve C is equal to the distance of P from the origin.Find curve C

A curve passing through the point (1,2) and satisfying the condition that slope of the normal at any abscissa of that point , then the curve also passes through the point