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A curve y=f(x) passes through (1,1) and ...

A curve `y=f(x)` passes through (1,1) and tangent at P(x,y) on it cuts x- axis and y-axis at A and B respectively such that `BP:AP=3:1` then the differential equation of such a curve is `lambda xy'+mu y=0` where `( mu + lambda -lambda^(2) ) / (mu - 2 lambda)` is .
Where `mu` and `lambda` are relatively prime natural

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