If `m=(lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta)))` then the value of `m` is

Let l=lim_(theta rarr0)(sin^(3)theta -tan^(3)theta)/(theta^(5)) and m=lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta)) .Find the value of [l^(2)+m^(2)] (where [x] denotes largest integer less than or equal to

If m=lim_(a rarr pi)(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta)) ,then the value of m is-

int_(0)^( pi)(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

lim_(theta rarr(pi)/(4))(1-tan theta)/(1-sqrt(2)sin theta)

lim_(theta rarr(pi)/(6))(4cos^(2)theta-3)/(2sin theta-1)

lim_(theta rarr0)(1-cos theta)/(sin^(2)2 theta)

lim_(theta rarr(pi)/(6))((sin(theta-(pi)/(6)))/(sqrt(3)-2cos theta)

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

evaluate lim_(theta rarr(pi)/(4))(sqrt(2)-cos theta-sin theta)/((4 theta-pi)^(2))

lim_(theta rarr pi)((sqrt(2)-cos theta-sin theta)/((4 theta-pi)^(2))