Home
Class 11
PHYSICS
A stone of mass 0.1kg is projected with...

A stone of mass `0.1kg` is projected with a velocity of ,`20sqrt(2)m/s` from the origin of an xy co-ordinate axis system at an angle of `45^(@)` with the horizontal.The angular momentum of the stone about the origin after 1 second is (take `g=10m/s^(2)` ):

Promotional Banner

Similar Questions

Explore conceptually related problems

A particle is projected with a speed 10sqrt(2) making an angle 45^(@) with the horizontal . Neglect the effect of air friction. Then after 1 second of projection . Take g=10m//s^(2) .

A projectile is thrown with a velocity of 20 m//s, at an angle of 60^(@) with the horizontal. After how much time the velocity vector will make an angle of 45^(@) with the horizontal (in upward direction) is (take g= 10m//s^(2))-

A particle is projected with a velocity of 10sqrt2 m//s at an angle of 45^(@) with the horizontal. Find the interval between the moments when speed is sqrt125 m//s(g=10m//s^(2))

A particle of mass 1 kg is projected at an angle of 30^(@) with horizontal with velocity v = 40 m/s . The change in linear momentum of the particle after time t = 1 s will be (g = 10 m// s^(2) )

A stone is projected with a velocity 20sqrt2 m//s at an angle of 45^(@) to the horizontal.The average velocity of stone during its motion from starting point to its maximum height is

A stone of mass 1 kg is thrown with a velocity of 20 m/s across the frozen surface of a take and it comes to rest after travelling a distance of 50 m . What is the magnitude of the force opposing the motion of the stone ?

A projectile is thrown with a velocity of 10sqrt(2)m//s at an angle of 45^(@) with horizontal. The interval between the moments when speed is sqrt(125)m//s is (g=10m//s^(2))