The work done by a force `F=2(x+4y)hat i+8xhat j N` on a particle moving from origin to `(4m,2m,0)` along the path `x^(2)=8y` is `10n` .Find the value of n

The work done by a force vec(F)=(-6x^(3)hat(i)) N in displacing a particle from x = 4m to x = - 2m is

The work done by a force on a body moving from (1,4) m to (3,8) m is 44 J. The force can be :

A force F = (2hat(i)+5hat(j)+hat(k))N is acting on a particle. The particle is first displacement from (0, 0, 0) to (2m, 2m, 0) along the path x = y and then from (2m, 2m, 0) to (2m, 2m, 2m) along the path x = 2m, y = 2 m. The total work done in the complete path is

A force vec F=(2 hat i + 3hat j \- 4 hat k)N acts on a particle moves 5 sqrt(2)m , the work done by force in joule is

A force vecF=(4hati+5hatj)N acts on a particle moving in XY plane. Starting from origin, the particle first goes along x-axis to the point (5.0) m and then parallel to the Y-axis to the point (5,4 m. The total work done by the force on the particle is

Calculate the work done by the force vec(F) = y hat(i) to move the particle from (0,0) to (1,1) in the following condition (a) y = x (b) y = x^(2)

A force F = (4.0 x hat(i) + 3.0 y hat(j)) N acts on a particle which moves in the x-direction from the origin to x = 5.0 m. Find the work done on the object by the force.

A force vec F=(6 hati -8 hatj)N , acts on a particle and displaces it over 4 m along the X-axis and 6 m along the Y-axis. The work done during the total displacement is

Consider a force overset ( r)(F)= -x^(3) hat( i) +y^(2) hat(j) .The work done by this force in moving a particle from A(1,0) to B(0,1) along a straight line is : ( All quantities are in SI units )