`(tan(B/2)-tan(C/2))/(tan(B/2)+tan(C/2))`

v) tan(A/2)tan(B/2)+tan(B/2)tan(C/2)+tan(C/2)tan(A/2)=1

If A+B+C=pi , prove that : tan( A/2) tan (B/2) + tan (B/2 )tan (C/2)+ tan( C/2) tan (A/2) =1

In triangle ABC, if |[1,1,1], [cot (A/2), cot(B/2), cot(C/2)], [tan(B/2)+tan(C/2), tan(C/2)+ tan(A/2), tan(A/2)+ tan(B/2)]| then the triangle must be (A) Equilateral (B) Isoceless (C) Right Angle (D) none of these

Prove that: tan(A+B)tan(A-B)=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

Prove that: (tan(A+B))/(cot(A-B))=(tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

If ABCD is a cyclic quadrilateral,the value of (tan(A)/(2)(tan)(C)/(2)+(tan)(B)/(2)(tan)(D)/(2) is

s^(2)tan((A)/(2))tan((B)/(2))tan((C)/(2))

In Delta ABC if tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))=(2)/(3) then a+c

In /_ABC with usual notations,if a,b,c are in A.P.then the numerical value of tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2)) is

tan((A)/(2))tan((B)/(2))+tan((B)/(2))tan((C)/(2))+tan((C)/(2) ))tan((A)/(2))=1