A body of mass `6kg` is under a force which causes displacement in it given by `S= (t^(2))/(4)` maters where `t` is time . The work done by the force in `2` sec is

A body of mass 3 kg is under a force , which causes a displacement in it is given by S = (t^(3))/(3) (in metres). Find the work done by the force in first 2 seconds.

A body of mass 3 kg is under a constant force which causes a displacement s metre in it, given by the relation s=(1)/(3)t^(2) , where t is in seconds. Work done by the force in 2 seconds is

A body of mass 5 kg at rest under the action of a force which gives its velocity given by v = 3 xx t m//s , here 't' is time in seconds. The work done by the force in two seconds will be

Under the action of a force a block of mass 2 kg is moved in such a way that its position is given by x=(t^(3))/3 metre. What is the work done by the force in the first two second?

A body of mass 4kg is acted upon by a force. The position of body with respect to time is denoted by x= (t^(4))/(4) . The work done by the force in first three seconds can be expressed in SI system as

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .