A ray of light passing through the point `(8,3)` gets reflected after it meets `x` -axis at `(14,0)` .Then the equation of the reflected ray

A ray of light passing through the point P(1,2) reflects on the x-axis at the point A and the reflected ray passes through the point Q(5,3). Find the coordinates of the point A

A ray of light passing through the point A(2,3) reflected at a point B on line x+y=0 and then passes through (5,3). Then the coordinates of B are

Statement I A ray of light incident at the point (-3,-1) gets reflected from the tangent at (0,-1) to the circle x^(2)+y^(2)=1 . If the reflected ray touches the circle, then equation of the reflected ray is 4y-3x=5 Statement II The angle of incidence = angle of reflection i.e. anglei=angler ,

A ray of light passing through the point (1,2) reflects on the x-axis at point A and the reflected ray passes through the point (5,3) Find the co-ordinates of A.

A ray of light passing through the point (1,2) reflects on the xaxis at point A and the reflected ray passes through the point (5,3) . Find the coordinates of A.

A ray of light incident at the point (-2,-1) gets reflected from the tangent at (0,-1) to the circle x^(2)+y^(2)=1. The reflected ray touches the circle.The equation of the line along which the incident ray moved is

A ray of light is sent along the line which passes through the point (2,3). The ray is reflected from the point P on x-axis.If the reflected ray passes through the point (6,4), then the co-ordinates of P are

A ray of light along x+sqrt(3)y=sqrt(3) gets reflected upon reaching x-axis,the equation of the reflected ray is

A ray of light passsing through a point (1,2) is reflected on the x-axis at point Q and passes through the point (5,8). Then the abscissa of the point Q is