If A and B are two invertible matrices of the same order, then adj (AB) is equal to

If A and B are invertible matrices of the same order, then (AB)^(-1) is equal to :

If A and B are invertible matrices of the same order, then (AB)' is equal to

If A and B are any two square matrices of the same order than ,

If A and B are non-singular square matrices of same order then adj(AB) is equal to

If A and B are two square matrices of the same order, then A+B=B+A.

If A and B are two matrices of the same order; then |AB|=|A||B|

If A and B are two invertible matrices of same order, the (AB)^-1 is (A) AB (B) BA (C) B^-1A^-1 (D) does not exist

If A and B are invertible matrices of the same order then (A) Adj(AB)=(adjB)(adjA) (B) (A+B)^-1=A^-1+B^-1 (C) (AB)^-1=B^-1A^-1 (D) none of these

If A and B are any two matrices of the same order, then (AB)=A'B'

If A and B are two invertible square matrices of same order, then what is (AB)^(-1) equal to ?