What is the energy of a photon that, when absorbed by a hydrogen atom, could cause an electronic transition from the `n=2` state to the `n=5` state?
0.86eV
0.472eV
1.92eV
10.2eV

Determine the energy of the photon (in eV) emitted when the electron in a hydrogen atom undergoes a transition from the n = 8 level to then = 6 level.

What is the energy, momentum and wavelength of the photon emitted by a hydrogen atom when an electron makes a transition from n=2 to n=1? Given that ionization potential is 13.6 eV

The energy of the ground state of hydrogen atom is -13.6 eV. The energy of the photon emitted in the transiton from n=4 to n=2 is

An electron is in the ground state of a hydrogen atom. A photon is absorbed by the atom and the electron is excited to the n= 2 state. What is the energy in eV of the photon?

A photon of energy 12.09 eV is completely absorbed by a hydrogen atom initially in the ground state. The quantum number of excited state is

The electron in a hydrogen atom at rest makes a transition from n = 2 energy state to the n = 1 ground state. find the energy (eV) of the emitted photon.

The ionisation potential of hydrogen atom is 13.6 eV The energy required to remve as electron in the n = 2 state of the hydrogen atom is

Energy of the lowest level of hydrogen atom is -13.6 eV . The energy of the photon emitted in the transition from n=3 to n=1 is

A photon of energy 10.5eV is allowed to interact with a hydrogen atom in its ground state. Then :