In a series LCR circuit `V_(1)`=3`V_(2)` and `V_(c)`=2`V_(R)` .If source has `V=110` sin ot,find the peak voltage across the capacitance.

Statement 1: In a series RLC circuit if (V_R), (V_L) and (V_C) denote rms voltage across R,L and C respectively and (V_S) is the rms voltage across the source. Then (V_s)=(V_R)+(V_L)+(V_C) Statement 2: In ac circuit, Kirchhoff's voltage law is correct at every instant of same.

In a series LCR circuit, V_(L) = V_(C ) != V_(R ) . What is the value of power factor ?

In series LCR circuit R=120 Omega and it has resonant frequency 4000 rad//sec . At resonance, the voltage across resistance and inductance is 60 V and 40 V respectively. Find the value of L and C in circuit.

In a series L-C circuit, the applied voltage is V_0. if omega is very low, then the voltage drop across the inductor V_L and capacitor V_C are .

In a series LCR circuit, the the rms voltage supply is 170 V. If V_(R), V_(L) and V_(C) represent the rms voltage drop across resistor , inductor and capacitor, then

In a series L-C-R circuit, currenrt in the circuit is 11A when the applied voltage is 220 V . voltage across the caspcitor is 200 V . If the value of resistor is 20 Omega , then the voltage across the unknown inductor is

In an LCR series ac circuit the voltage across L,C and R are V_(1), V_(2) and V_(3) respectively The voltage of the source is .

An ac source of 50 V (r.m.s value) is connected across a series R - C circuit. If the r.m.s voltage across the resistor is 40 V, then the r.m.s voltage across the capacitor is

Consider a series LCR circuit connected to an AC supply of 220V. If voltage drop across resistance R is V_R, voltage drop across capacitor is V_c =2V_R and that across inudctor coil is V_L = 2V_R then choose correct alternative(s)