If the tangents at two points `(1,2) and (3,6)` on a parabola intersect at the point `(-1,1),` then ths slope of the directrix of the parabola is

If the points A (1,3) and B (5,5) lying on a parabola are equidistant from focus, then the slope of the directrix is

Let A(4,-2) and B(0,1) are two points on the parabola,normals at which intersect at the point P(2,2). The equation of directrix of the parabola is (A)((6)/(5),-(6)/(5))(B)((16)/(5),-(7)/(5)) (C) ((12)/(5),-(6)/(5))(D)(-(6)/(5),(6)/(5))

If the points (2,3) and (3,2) on a parabola are equidistant from the focus, then the slope of its tangent at vertex is

y= -2x+12a is a normal to the parabola y^(2)=4ax at the point whose distance from the directrix of the parabola is

Prove that the normals at the points (1,2) and (4,4) of the parabola y^(2)=4x intersect on the parabola

Let y=3x-8 be the equation of the tangent at the point (7, 13 ) lying on a parabola whose focus is at (-1,-1). Find the equation of directrix and the length of the latus rectum of the parabola.

Tangent drawn at point P(1,3) of a parabola intersects its tangent at vertex at M(-1,5) and outs the axis of parabola at T.If R(-5,5) is a point on SP; where S is focus of the parabola,then