If `A-B=(2n+1)(pi)/(2)` ,`n in Z` ,then `[[cos^(2)A,cos A sin A],[cos A sin A,sin^(2)A]][[cos^(2)B,cos B sin B],[cos B sin B,sin^(2)B]]=`

sin^(2)A cos^(2)B-cos^(2)A sin^(2)B=sin^(2)A-sin^(2)B

Prove that: cos^(2)A+cos^(2)B-2cos A cos B cos(A+B)=sin^(2)(A+B)

If det [[cos (A + B), - sin (A + B), cos2Bsin A, cos A, sin B-cos A, sin A, cos B]] = 0

If det [[cos (A + B), - sin (A + B), cos2Bsin A, cos A, sin B-cos A, sin A, cos B]] = 0

cos2a-cos2b + cos2c = 1-4sin a cos b sin c

If A+B+C = pi , show that |["sin"^(2)A, "sin A cos A", "cos"^(2)A],["sin"^(2) B, "sin B cos B", "cos"^(2)B],["sin"^(2)C, "sin C cos C", "cos"^(2)C]| =-"sin (A-B)"sin"(B-C)"sin"(C-A)"

(cos A + cos B) ^ (2) + (sin A + sin B) ^ (2)

sin ^ (2) A cos ^ (2) B + cos ^ (2) A sin ^ (2) B + sin ^ (2) A sin ^ (2) B + cos ^ (2) A cos ^ (2) B =

(cos A)/(sin B sin C)+(cos B)/(sin C sin A)+(cos C)/(sin A sin B)=2

If sin A=a cos B and cos A=b sin B then tan^(2)B =