in `DeltaABC , (s-a)/Delta = 1/8 ,(s-b)/Delta = 1/12 ,(s-c)/Delta = 1/24` then `b=`

In triangleABC," if"(s-a)/(Delta)=1/8, (s-b)/(Delta)=1/12 and (s-c)/(Delta)=1/24 , then b=

Delta ABC,(s-a)/(Delta)=(1)/(8),(s-b)/(Delta)=(1)/(12),(s-c)/(Delta)=(1)/(24) then b=

If p_1,\ p_2,\ p_3 are the altitudes of a triangle from its vertices A ,\ B ,\ C and "Delta" , the area of the triangle A B C , then 1/(p_1)+1/(p_2)-1/(p_3) is equal to s/"Delta" (b) (s-c)/"Delta" (c) (s-b)/"Delta" (d) (s-a)/"Delta"

If in a triangle ABC,(s-a)/(11)=(s-b)/(12)=(s-c)/(13) .and k tan^(2)(A/2)=429, then (sqrt(k))/(11)

Statement I If the sides of a triangle are 13, 14 15 then the radius of in circle =4 Statement II In a DeltaABC, Delta = sqrt(s (s-a) (s-b) (s-c)) where s=(a+b+c)/(2) and r =(Delta)/(s)

In Delta ABC, a^(2)(s-a)+b^(2)(s-b)+c^(2)(s-c)=

In a triangle A B C ,(r_1+r_2)/(1+cosC) is equal to (2a b)/(c"Delta") (b) ((a+b))/(c"Delta") (a b c)/(2"Delta") (d) (a b c)/("Delta"^2)

If in Delta ABC, (a -b) (s-c) = (b -c) (s-a) , prove that r_(1), r_(2), r_(3) are in A.P.

A reaction attains equilibrium state under standard conditions, then A) equilibrium constant K=0 B) equilibrium constant "K=1 C) Delta G^(o)=0 and Delta H^(o)=T Delta S^(o) D) Delta G=0 and Delta H = T Delta S