A force of `(4x^(2)+3x)N` acts on a particle which displaces it from `x=2m` to `x = 3m`. The work done by the force is

A force of 3x^(2)-2x+5 acts on a body of mass 5 kg and displaces it from x=0 to x=4 m. What is the work done by the force?

A positon dependent force , F=8-4x+3x^(2)N acts on a small body of mass 2 kg and displaces it from x=0 to x=5 m. The work done in joule is

Consider a variable force F=(3x+5)N acting on a body and if it is displaced from x=2m to x=4m , calculate the work done by this force.

A force vecF=(7-2x+3x^(2)) N is applied on a 2 kg mass which displaces it from x = 0 to x = 5 m. Work done in joule is -

A force vecF=(3x^(2)+2x-7)N acts on a 2 kg body as a result of which the body gets displaced from x=0 to x=5m. The work done by the force will be –

A force F = p+qx acts on a particle in the X - direction , where p and q are constants . If the particle is displaced from x = a to x = b , find the work done by the force .

A force f =10 + 2 x acts on a particle moving in straight line on x axis the work done by this force during a displacement from x =0 and x =3m