The position of a particle moving along the y-axis is given as `y=3t^(2)-t^(3)` where `y` is in , metres and t is in sec.The time when the particle attains maximum positive y position will be

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

The position of the particle moving along Y -axis is given as y=At^(2)-Bt^(3) , where y is measured in metre and t in second. Then, the dimensions of B are

Position of particle moving along x-axis is given as x=2+5t+7t^(2) then calculate :

The position of a particle with respect to time t along y-axis is given by : y = 12t^2 – 2t^3 , where, y is in metres and t is in seconds. When the particle achieves maximum speed, the position of the particle would be

Position of a particle moving along x-axis is given by x=6t-t^(2)+4 , where x is in metre and t is in second. Which of the following is correct?

The position x of a particle with respect to time t along x-axis is given by x=9t^(2)−t^(3) where x is in metres and t is in seconds. What will be the position of this pariticle when it achieves maximum speed along the + x direction ?

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

The position x of a particle with respect to time t along the x-axis is given by x=9t^(2)-t^(3) where x is in meter and t in second. What will be the position of this particle when it achieves maximum speed along the positive x direction

Position of a particle moving in a straight line is given as y = 3t^3 + t^2 (y in cm and t in second) then find acceleration of particle at t = 2sec