The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

The position of a particle moving along an x axis is given by x=12t^(2)-2t^(3) , where x is in meters and t is in seconds. Determine (a) the position, (b) the velocity, and (c) the acceleration of the particle at t=3.5s . (d) What is the maximum positive coordinate reached by the particle and (e) at what time is it reached ? (f) What is the maximum positive velocity reached by the particle and (g) at what time is it reached ? (h) What is the acceleration of the particle at the instant the particle is not moving ( other than at t=0 ) ? (i) Determine the average velocity of the particle between t=0 and t=3 s .

Position of particle moving along x-axis is given by x=2t^(3)-4t+3 Initial position of the particle is

Position of a particle moving in a straight line is given as y = 3t^3 + t^2 (y in cm and t in second) then find acceleration of particle at t = 2sec

Position of a particle moving along x-axis is given by x=6t-t^(2)+4 , where x is in metre and t is in second. Which of the following is correct?

The position x of a particle with respect to time t along x-axis is given by x=9t^(2)−t^(3) where x is in metres and t is in seconds. What will be the position of this pariticle when it achieves maximum speed along the + x direction ?

The position x of a particle with respect to time t along the x-axis is given by x=9t^(2)-t^(3) where x is in meter and t in second. What will be the position of this particle when it achieves maximum speed along the positive x direction