`KMnO_(4)+HCl rarr MnCl_(2)+X_((g))+Y+H_(2)O`
`"X"` is a

If 1 g of HCl and 1 g of MnO_(2) heated together the maximum weight of Cl_(2) gas evolved will be : [MnO_(2) + 4HCl rarr MnCl_(2) + Cl_(2) + 2H_(2)O] :

In the following reaction, MnO_(2) + 4HCl rarr MnCl_(2) + 2H_(2)O + Cl_(2) 2 mole MnO_(2) reacts with 4 mol of HCl to form 11.2 L Cl_(2) at STP. Thus, percentage yield of Cl_(2) is:

20 gm pyrolusite ore exactly requires 29.2 gm HCl for complete reaction : MnO_(2)+4HCl rarr MnCl_(2)+Cl_(2)+2H_(2)O The mass percent of pure MnO_(2) in the pyrolusite ore is (Mn = 55)

An unknown compound A (Mn_(x)O_(y)) composed of manganese and oxygen , has 36.7% oxygen by weight. When 8.7 g of A is heated with HCl it liberates Cl_(2) gas as per the following reaction: Mn_(x)O_(y) +HCl rarr MnCl_(2)+Cl_(2)+H_(2)O (unbalanced) The simplest formula of A is:

KMnO_(4)+H_(2)O_(2) rarr Mn^(2+)-O_(2)

An unknown compound A (Mn_(x)O_(y)) composed of manganese and oxygen , has 36.7% oxygen by weight. When 8.7 g of A is heated with HCl it liberates Cl_(2) gas as per the following reaction: Mn_(x)O_(y) +HCl rarr MnCl_(2)+Cl_(2)+H_(2)O (unbalanced) The volume of Cl_(2) gas at STP obtained when 8.7 gm of compound A is heated with excess of HCl , (assume molecular formula and , empirical formula to be same):

Balance the following equations by hit and trial method: (a) KMnO_(4) + HCl to KCl + MnCl_(2) + H_(2)O + Cl_(2) (b) H_(2)S + SO_(2) to S + H_(2)O ( c) K_(2)Cr_(2)O_(7) + H_(2)SO_(4) to K_(2)SO_(4) + Cr_(2)(SO_(4))_(2) + H_(2)O + O_(2) (d) KMnO_(4) + KOH to K_(2)MnO_(4) + O_(2) + H_(2)O (e) Mg_(3)N_(2) + H_(2)O to Mg(OH)_(2) + NH_(3) (f) Al_(4)C_(3) + H_(2)O to Al(OH)_(3) + CH_(4) (g) FeS_(2) + O_(2) to Fe_(2)O_(3) + SO_(2) (h) KMnO_(4) + H_(2)S + H_(2)SO_(4) to KHSO_(4) + MnSO_(4) + S + H_(2)O (i) C_(3)H_(8)(g) + O_(2)(g) to CO_(2)(g) + H_(2)O(l)

Balance the following reactions by oxidation number method KMnO_(4) + H_(2)SO_(4) +HCl rarr K_(2) SO_(4) + MnSO_(4) + H_(2) O + Cl_(2)