If `m=lim_(a rarr pi)(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta))` ,then the value of `m` is-

If m=(lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta))) then the value of m is

Let l=lim_(theta rarr0)(sin^(3)theta -tan^(3)theta)/(theta^(5)) and m=lim_(theta rarr(pi)/(4))(((sin theta+cos theta)^(3)-2sqrt(2))/(1-sin2 theta)) .Find the value of [l^(2)+m^(2)] (where [x] denotes largest integer less than or equal to

int_(0)^( pi)(sin theta+cos theta)/(sqrt(1+sin2 theta))d theta

If sin theta cos theta=sqrt(2)cos theta then the value of sin theta+cos theta is

If cos theta+sqrt3 sin theta=2 , then the value of theta is equal to

(sin3 theta+cos3 theta)/(cos theta-sin theta)=1+2xx sin2 theta

lim_(theta rarr0)((sin theta)/(sin((theta)/(2))))=2

lim_(theta rarr(pi)/(6))((sin(theta-(pi)/(6)))/(sqrt(3)-2cos theta)

(1+sin2 theta-cos2 theta)/(1+sin2 theta+cos2 theta)=tan theta

2(cos theta+cos2 theta)+(1+2cos theta)sin2 theta=2sin theta