If the points `1+2i` and `-1+4i` are reflections of each other in the line `z(1+i)+bar(z)(1-i)+k=0` then the value of `k` is

if the point z_(1)=1+i where i=sqrt(-1) is the reflection of a point z_(2)=x+iy in the line ibar(z)-iz=5 then the point z_(2) is

If ((1+i) z= (1-i))bar(z), then

If (4+i)(z+bar(z))-(3+i)(z-bar(z))+26i = 0 , then the value of |z|^(2) is

If z= 1/((1+i)(1-2i)) , then |z| is

If (1+i)z=(1-i)bar(z) then z is

if (1+i)z=(1-i)bar(z) then z is

If | (z - i)/(z + 2i)| = 1, |z| = 5/2 then the value of |z + 3i|

If z_(2) be the image of a point z_(1) with respect to the line (1-i)z+(1+i)bar(z)=1 and |z_(1)|=1 , then prove that z_(2) lies on a circle. Find the equation of that circle.

If |z - 1| = |z + 1| = |z - 2i|, then value of |z| is