At `t=0` a projectile is fired from a point `O` (taken as origin) on the ground wita speed of `50m//s` at an angle of `53^(@)` with the horizontal. It just passes two points `A` and `B` each at height `75m` above horizontal.

The horizontal separation between the points `A` and `B`

At t=0 a projectile is fired from a point O (taken as origin) on the ground wita speed of 50m//s at an angle of 53^(@) with the horizontal. It just passes two points A and B each at height 75m above horizontal. The distance (in metre) of the particle from origin at t=2s

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

A particle is fired from a point on the ground with speed u making an angle theta with the horizontal.Then

A projectile is thrown from the ground with a speed of 2sqrtgh at an angle of 60^@ to the horizontal from a point on the horizontal ground . The horizontal range of the projectile is

A projectile of mass "m" is projected from ground1 with a speed of 50 m/s at an angle of 53^(@) with the horizontal. It breaks up into two equal parts at the highest point of the trajectory. One particle coming to rest immediately after the explosion. The distance between the pieces of the projectile when they reach the ground are :

A ball is projected form top of a tower with a velocity of 5m//s at an angle of 53^(@) to horizontal. Its speed when it is at a height of 0.45m from the point of projection is:

A bomb is fired from a cannon with a velocity of 1000 m/s making an angle of 30^@ with the horizontal. What is the time taken by the bomb to reach the highest point?

From the ground, a projectile is fired at an angle of 60 degree to the horizontal with a speed of 20" m s"^(-1) The horizontal range of the projectile is