If `a ,\ b ,\ c >0` such that `a+b+c=a b c` , find the value of `tan^(-1)a+tan^(-1)b+tan^(-1)c` .

If sqrt(3)+i=(a+ib)(c+id), then find the value of tan^(-1)(b/a)+tan^(-1)(d/c)

If a,b,c be positive real numbers and the value of theta=tan^(- 1)sqrt((a(a+b+c))/(b c))+tan^(- 1)sqrt((b(a+b+c))/(c a)) + tan^-1sqrt((c(a+b+c))/((ab)) then tan theta is equal to

If a,b,c be positive real numbers and the value of theta=tan^(- 1)sqrt((a(a+b+c))/(b c))+tan^(- 1)sqrt((b(a+b+c))/(c a)) + tan^-1sqrt((c(a+b+a))/((ab)) then tan theta is equal to

If A+B=C, then write the value of tan A tan B tan C.

tan^(-1)( (a+b tan c)/ (b-a tan x) )

Tan (A-B) + Tan (B-C) + Tan (C-A)

In a A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))=

If tan^(-1) a+tan^(-1) b +tan^(-1)c=pi , prove that a+b+c=abc.