[" Find the free energy for a reaction having "],[Delta H=31400" cal."Delta S=32" cal "k^(-1)mol^(-1)" at "1000^(@)C]

The free energy for a reaction having DeltaH=31400 cal, DeltaS=32" cal "K^(-1)mol^(-1) at 1000^(@)C is:

The free energy for a reaction having DeltaH=31400 cal, DeltaS=32" cal "K^(-1)mol^(-1) at 1000^(@)C is:

The change in Gibbs free energy of the system along provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a sytem at constant temperature and pressure will be: DeltaG_("system") = DeltaH_("system") - T DeltaS_("system") The free energy for a reaction having Delta H= 31400 cal, DeltaS= 32 cal K^(-1) mol^(-1) at 1000^(@)C is

The change in Gibbs free energy of the system along provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a sytem at constant temperature and pressure will be: DeltaG_("system") = DeltaH_("system") - T DeltaS_("system") The free energy for a reaction having Delta H= 31400 cal, DeltaS= 32 cal K^(-1) mol^(-1) at 1000^(@)C is

The change in Gibbs free energy of the system alone provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a system at constant temperature and pressure will be : DeltaG_("system")=DeltaH_("system")-T DeltaS_(system") The free energy for a reaction having DeltaH=31400 cal, DeltaS=32 cal L^(-1) mol^(-1) at 1000^(@)C

A change in the free energy of a system at constant temperature and pressure will be: Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S At constant temperature and pressure Delta_(sys) G lt 0 (spontaneous) Delta_(sys)G = 0 (equilibrium) Delta_(sys)G gt 0 (non-spontaneous) The free enegry for a reaction having DeltaH = 31400 cal, DeltaS = 32 cal K^(-1) mol^(-1) at 1000^(@)C is

A change in the free energy of a system at constant temperature and pressure will be: Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S At constant temperature and pressure Delta_(sys) G lt 0 (spontaneous) Delta_(sys)G = 0 (equilibrium) Delta_(sys)G gt 0 (non-spontaneous) The free enegry for a reaction having DeltaH = 31400 cal, DeltaS = 32 cal K^(-1) mol^(-1) at 1000^(@)C is