" If "A+B=(pi)/(2)" then "tan B+2tan(A-B)

If A+B=pi//2 then tan B+ 2 tan (A-B)=

If A+B+C=(pi)/(2) then tan2A+tan2B+tan2C=

if A-B=(pi)/(4) and A+B=(pi)/(3) then (tan^(2)A-tan^(2)B)/(1-tan^(2)A tan^(2)B)

If A+ B+C= pi//2 , " then " tan 2A + tan 2B+ tan 2C=

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , x= Tan""(5 pi)/(28)+2Tan""(pi)/(7) Then x

If A+B=(pi)/(2)rArr Tan A Tan B=1 , rArr Tan(A-B)=(tan A-tan B)/(1+tan A tan B)=(tan A-tan B)/(2) , rArr tan A=tan B+2tan(A-B) , (tan40^(@)+2tan10^(@))*(tan70^(@)-Tan20^(@))=

If 2A + B = (pi)/(2) or (3pi)/(2) then show that tan A + 2 tan B = tan (A +B).

A + B + C = (pi) / (2) rArr tan A tan B + tan B tan C + tan C tan A =

If A+B+ C=(pi)/(2) then what is the value of tan A tan B +tan B. tan C + tan C tan A?