What is approx. the centripetal acceleration (in units of acceleration due to gravity on earth, `g=10ms^(-2)`) circular acr of radius 0.6 km?

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g = 10 m s^(-2) ) of an air-craft flying at a speed of 400 m s^(-1) through a circular arc of radius 0.6 km ?

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth, g = 10 m s^(-2) of an air-craft flying at a speed of 400 m s^(-1) through a circular arc of radius 0.6 km ?

What is approximately the centripetal acceleration (in units of acceleration due to gravity on earth g = 10 m s^-2 ) of an aircraft flying at a speed of 400 m s^-1 through a circular are of radius 0.6 km.

If R is the radius of the earth and .g. the acceleration due to gravity, the mass of the earth is

The acceleration due to gravity on a planet of mass 10^(25) Kg and radius 2580 Km in ms^(-2) is

Calculate the acceleration due to gravity at a height of 1600 km from the surface of the Earth. (Given acceleration due to gravity on the surface of the Earth g_(0) = 9.8 ms^(-2) and radius of earth, R = 6400 km).

What will be the acceleration due it gravity at a depth in Earth. where g is acceleration due to gravity on the earth ?

If radius of the earth is 6347 km, then what will be difference between acceleration of free falls and acceleration due to gravity near the earth's surface?