Prove that the product of the perpendiculars from `(alpha,beta)` to the pair of lines `a x^2+2h x y+b y^2=0` is `(aalpha^2-2halphabeta+bbeta^2)/(sqrt((a-b)^2+4h^2))`

Prove that the product of the perpendiculars from (alpha,beta) to the pair of lines ax^(2)+2hxy+by^(2)=0 is (a alpha^(2)-2h alpha beta+b beta^(2))/(sqrt((a-b)^(2)+4h^(2)))

The product of the perpendiculars from (-1,2) to the pair of lines 2x^(2)5xy+2y^(2)=0

The product of the perpendiculars drawn from (2,-1) to the pair of lines x^(2)-3xy+2y^(2)=0 is

The product of the perpendiculars drawn from the point (1,2) to the pair of lines x^(2)+4xy+y^(2)=0 is

If the product of perpendiculars from (k,k) to the pair of lines x^(2)+4xy+3y^(2)=0 is (4)/(sqrt(5)) then k is

The product of the perpendicular distances from the point (-2,3) to the lines x^(2)-y^(2)+2x+1=0 is

The product of the perpendiculars from the point (1,1) to the pair of straight lines represented by 2x^(2)+6xy+3y^(2)=0 is

The equation to the pair of lines perpendicular to the pair of lines 3x^(2)-4xy+y^(2)=0 , is

Prove that the product of the perpendiculars from the foci upon any tangent to the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 is b^(2)

Prove that the product of the length of the perpendiculars from the points (sqrt(a^2 -b^2) , 0) and (-sqrt(a^2 -b^2), 0) to the line x/a cos theta + y/a cos theta + y/b sin theta = 1 is