x^(2)-8x+12

The vertex of the parabola x^(2)+8 x+12 y+4=0 is

Factorize the following polynomials. (x^2 -x)^2 -8(x^2 -x) +12

Factorise : (2x-3)^2-8x+12

Factorize (2x-3)^2-8x+12 .

Factorize the polynomial. (x^2-x)^2-8(x^2-x)+12

Find the HCF of 15x^(2) + 8 x - 12, 3x^(2) + x - 2,3x^(2) - 2x , 9x^(2) - 12 x + 4

Sum of all the solution of the equation ([x])/([x-2])-([x-2])/([x])=(8{x}+12)/([x-2][x]) is (where{*} denotes greatest integer function and {*} represent fractional part function)

Sum of all the solution of the equation ([x])/([x-2])-([x-2])/([x])=(8{x}+12)/([x-2][x]) is (where {*} denotes greatest integer function and {^(*)} represent fractional part function)