Find the image of the circle `x^2+y^2-2x+4y-4=0` in the line `2x-3y+5=0`

The equatioin of the image of the circle x^(2)+y^(2)+016x-24y+183=0 in the line mirror 4x+7y+13=0 is: a.x^(2)+y^(2)+32x-4y+235=0 b.x^(2)+y^(2)+32x-4y-235=0cx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x-4y-235=0dx^(2)+y^(2)+32x+4y+235=0

For the circle x^(2)+y^(2)-2x-4y-4=0 ,the lines 2x+3y-1=0,2x+y-1=0 are

Find the equation of the circle through points of intersection of the circle x^(2)+y^(2)-2x-4y+4=0 and the line x+2y=4 which touches the line x+2y=0.

The equation of the image of the circle x^(2)+y^(2)-6x-4y+12=0 by the mirror x+y-1=0 is

the image of the parabola y^(2)=x in the line x+y+4=0 is

Point on the circle x^(2)+y^(2)-2x+4y-4=0 which is nearest to the line y=2x+11 is :

Find the equation of the circle with centre on the line 2x + y = 0 and touching the line 4x - 3y + 10-0, 4x - 3y = 30 .

Find the equation of line joining the center of the circles x^(2)+y^(2)-2x+4y+1=0 and 2x^(2)+2y^(2)-2y+4x+1=0

A line L is perpendicular to the line 3x-4y-7=0 and touches the circle x^(2)+y^(2)-2x-4y-4=0 , the y -intercept of the line L can be: