At a certain point the angle of elevation of a tower is found to be `cot^-1(3/5).`On walking 32 metres directly towards the tower its angle of elevation is `cot^-1(2/5).`The height of the tower in metres is

At a point A , the angle of elevation of a tower is such that its tangerit is 5/(12) , on walking 120 m nearer the tower the tangent of the angle of elevation is 3/4 . The height of the tower (in metres) is

The angle of elevation of the top of a tower at a point G on the ground is 30^(@) . On walking 20 m towards the tower the angle of elevation becomes 60^(@) . The height of the tower is equal to :

At a point A, the angle of elevation of a tower is such that tangent is 5/12, on walking 240 m nearer the tower, the tangent of the angle of elevation is 3/4 Then the height in m) of the tower is:

The angle of elevation of the top of a tower at a point on the ground is 30o.On walking 24m towards the tower,the angle of elevation becomes 60_(0). Find the height of the tower.

At a point on level ground,the angle of elevation of a vertical tower is found to be such that its tangent is 5/12. On walking 192 metres towards the tower,the tangent of the angle of elevation is 3/4. Find the height of the tower.

At a point, the angle of elevation of a tower is such that its tangent is 5/12 . On walking 240 m nearer to the tower, the tangent of the angle of elevation becomes 3/4 . Find the height of the tower.