`(sin^4theta-cos^4theta)/(sin^2theta-cos^2theta)=1`

Prove the following identities: 2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta)+1=0 sin^6theta+cos^6theta+3sin^2thetacos^2theta=1 (sin^8theta-cos^8theta)=(sin^2theta-cos^2theta)(1-2s in^2thetacos^2theta)

Prove that (sin^(4)theta-cos^(4)theta)/(sin^(2)theta-cos^(2)theta)=1

Prove that sin^4theta-cos^4theta=sin^2theta-cos^2theta .

Prove the following: sin^4theta+cos^4theta=1-2sin^2thetacos^2theta

Prove that sin^4theta+cos^4theta=1-2sin^2thetacos^2theta .

The value for 2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) +1 is

If : sin^(4)theta+cos^(4)theta+sin^(2)theta*cos^(2)theta=1-u^(2), "then" : u=

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to

Show : Sin^4theta - Cos^4theta = Sin^2theta - Cos^2theta

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है: