" Base angles of triangle are "22(1)/(2)" ' and "112(1)/(2)" ",then the height of the triangle is "

If the base angles of triangle are 22 1/2a n d112 1/2 , then prove that the altitude of the triangle is equal to 1/2 of its base.

If the base angles of a triangle are 22(1)/(2),112(1)/(2) then third angle is

The base angle of triangle are 22 (1)/(2)^@ and 112 (1)/(2)^@ if b is the base and h is the height of the triangle , then

If the base angles of triangle are ((22)/(12))^@ and (112 1/2)^@ , then prove that the altitude of the triangle is equal to 1/2 of its base.

If the base angles of triangle are ((22)/(12))^@ and (112 1/2)^@ , then prove that the altitude of the triangle is equal to 1/2 of its base.

If the base angles of triangle are ((22 1/2))^@ and (112 1/2)^@ , then prove that the altitude of the triangle is equal to 1/2 of its base.

If the base angles of a triangle are 22 (1^(0) )/(2) , 112 (1^(0))/(2) , then base and height are in the ratio

If the base angles of triangle are ((22)/(12))^(@) and (112(1)/(2))^(@), then prove that the altitude of the triangle is equal to (1)/(2) of its base.

The base angle of triangle are 22 (1^(@))/(2) and 112 (1^(@))/(2). If b is the base and h is the height of the triangle, then : a) b=2h b)b=3h c) b (1 + sqrt3) h d) b = (2 + sqrt3) h