[" 17.The point "(-1,0)" lies op the circle "x^(2)+y^(2)-4x+8y+k=0" .The radius of the circle is "],[[" ) "4," (4) "5," (3) "3," none "]]

The point (-1,0) lies on the circle x^2+y^2-4x+ 8y + k=0 . The radius of the circle is

The point (1,2) lies inside the circle x^(2)+y^(2)-2x+6y+1=0 .

The point (1,2) lies inside the circle x^(2) + y^(2) - 2x + 6y + 1 = 0 .

The point (2, -1) ________ the circle x^(2) + y^(2) - 4x + 6y + 8 = 0 .

The point P(-1,0) lies on the circle x^(2)+y^(2)-4x+8y+k=0 . Find the radius of the circle Also determine the equation of the circle of equal radius which touches the given circle at P.

The radius of the circle 3x^(2)+3y^(2)+9x+8y-4=0 is

Find the centre and radius of the circle x^(2)+y^(2)-4x-8y-45=0 ?

Find the centre and radius of the circles x^(2)+y^(2)-4x-8y-45,=0