" Q."11" Find "(ity)/(4x)" if "x*sqrt(xy)+y=1

find dy/dx if x+ sqrt (xy) + y = 1

find the derivative; sqrt(xy) = e^((x-y))

The equation oi the conic with focus at (1,-1) directrix along x-y+1=0 and eccentricity sqrt(2) is xy=1 b.2xy+4x-4y-1=0cx^(2)-y^(2)=1 d.2xy-4x+4y=1=0

Q. 11 The solution of (dy)/(dx)=(2x-y+3)/(x+2y+4) is y^(2)-x^(2)+xy+4y-3x+1=C x^(2)-y^(2)+xy+4y+3x-1=C y^(2)-x^(2)-xy-4y+3x-1=C y^(2)-x^(2)+xy+4y-3x-1=C

If x,y in R satisfy the equation x^2 + y^2 - 4x-2y + 5 = 0, then the value of the expression [(sqrtx-sqrty)^2+4sqrt(xy)]/((x+sqrt(xy)) is

f(x)+f(y)=f((x+y)/(1-xy)) ,for all x,yinR . (xy!=1) ,and lim_(x->0) f(x)/x=2 .Find f(sqrt3) and f'(-2) .

If sqrt(x)+sqrt(y)=17 and sqrt(x)-sqrt(y)=1, then the value of is sqrt(xy)

If x,y in R satify the equation x^(2)+y^(2)-4x-2y+5=0, then the value of the expression [(sqrt(x)-sqrt(y))^(2)+sqrt(xy)]/(x+4sqrt(xy)) is sqrt(2)+1 b.(sqrt(2)+1)/(2) c.(sqrt(2)-1)/(2) d.(sqrt(2)+1)/(sqrt(2))