It is given that `Delta ABC~Delta PRQ and (BC)/(QR)=(2)/(3) " then " (ar (Delta PQR))/(ar (Delta ABC))=?`

It is given that Delta ABC - Delta PQR , with (BC)/(QR) = (1)/(4) . Then (ar Delta PQR)/(ar Delta ABC) is equal to:

If Delta ABC ~ Delta PQR with (BC)/(QR) = 1/3 , then find (ar Delta PRQ)/(ar Delta BCA) ?

If triangle ABC - triangle PQR and (BC)/(QR) = 1/4 then (ar(trianglePQR))/(ar(triangleABC)) =

In Figure 1,PQ|BC and AP:PB=1:2* find the ratio of (ar Delta APQ)/(ar Delta ABC)

In Delta ABC and Delta DEF , we have (AB)/(DE)=(BC)/(EF)=(AC)/(DF)=5/7 , then ar (Delta ABC) : ar (Delta DFR) =?

Given triangle ABC ~ triangle PQR if (AB)/(PQ)=1/3 then find (ar triangle ABC)/(ar triangle PQR)

In Delta ABC,AD and BE are altitudes.Prove that (ar(Delta DEC))/(ar(Delta ABC))=(DC^(2))/(AC^(2))

Delta ABC ~ Delta PQR and ar(DeltaABC)=4ar(DeltaPQR) IF BC=12cm then find QR

Delta ABC and Delta BDC are on the same base BC. Prove that (ar(Delta ABC))/(ar(Delta DBC)) =(AO)/(DO)

The base BC of Delta ABC is divided at D, so that BD=(1)/(2)DC. Prove that ar(Delta ABD)=(1)/(3)ar(Delta ABC)