" A is a square matrix of order "n times n" and "k" is a scalar,then adj "(kA)" is equal to "

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A is a square matrix of order n xx n and k is a scalar, then adj (kA) is equal to (1) k adj A (2) k^n adj A (3) k^(n-1) adj A (4) k^(n+1) adj A

If A is a square matrix of order nxxn and k is a scalar, then adj(kA)=

If A is a square matrix of order n, then |adj A|=

If A is a square matrix of order n then |kA|=

If A is a square matrix of order 3xx3 and lambda is a scalar, then adj (lambdaA) is equal to -

If A is a square matrix of order 2, then adj (adj A)

If A=[a_(ij)] is a square matrix of order nxxn and k is a scalar then |kA|=