I=int sin^(4)ndn

int sin^(4)x*dx

obtain reducation formula for I_(n)=int sin^(4)dx Hence evaluate int sin^(4)xdx

int sin ^ (4) xdx

int sin ^ (4) xdx

int sin^(4)(sin^(-1)x)dx

I_(n)=int sin^(n)xdx

I= int sin^(2) 3x dx .

I=int sin^(-1)(2x)dx

If I_(1)=int sin^(-1)x dx and I_(2)=int sin^(-1) sqrt(1-x^(2)) dx then -

Method of integration by parts : I_(1)=int sin^(-1)x dx and I_(2)= int sin^(-1) sqrt(1-x^(2))dx then.....