(1)/(3-10x-25x^(2))dx

int(dx)/(3-10x-25x^2)=

int (dx)/(16-25x^(2))

If y=tan^(-1)((4x)/(1+5x^(2)))+tan^(-1)((2+3x)/(3-2x)) , then (dy)/(dx) is equal to a) (5)/(1+25x^(2)) b) (1)/(1+25x^(2)) c)0 d) (5)/(1-25x^(2))

The number of terms in the expansion of (1-10x+25x^(2))^(20) is

sin^(-1)((1-25x^(2))/(1+25x^(2))) differentiate

Evaluate: (i) int(1)/(sqrt(9-25x^(2)))dx (ii) int(1)/(sqrt(16x^(2)+25))dx

int((1)/(sqrt(9-25x^(2))))dx

"int(x^(2))/(sqrt(9-25x^(2)))dx