Find the surface area of a sphere when its volume is changing at the same rate as its radius.

What is the surface area of a sphere when the volume is increasing at the same rate as its radius?

Find the rate of the change of surface area of a sphere when its radius is increasing at the rate of 3/pi cm/min and its radius is 1 cm.

The rate of change of the surface area of a sphere of radius r when the radius is increasing at the rate of 2cm/sec is proportional to

If the volume and surface area of a sphere are numerically the same, then its radius is

The rate of change of surface area of a sphere of radius r when the radius is increasing at the rate of 2 cm/s. is proportional to

The rate of change of surface area of a sphere of radius r when the radius is increasing at the rate of 2 cm/sec is proportional to

The rate of change of surface area of a sphere of radius r when the radius is increasing at the rate of 2 cm/sec is proportional to

If the surface area of a sphere of radius r is increasing uniformly at the rate cm^(2)//s , then the rate of change of its volume is :