A potentiometer wire is `100 cm` long hand a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obatined at `50 cm` and `10 cm` from the positive end of the wire in the two cases. The ratio of emfs is:

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in the two cases. The ratio of emf's is :

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 64 cm and 32 cm from the positive end of the wire in the two cases. the ratio of emf's is

A potentiometre wire is 100 cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction.The balance points are obtained at 50 cm and 10 cm from the positive end of the wire in two cases. The ration of emf's is

A poterntimeter wire is 100 cm long and a constant potential difference is maintained acrooss it . Two cells are connected in seires first to support one another and then in opposite direction . The balance points are obtained at 50 cm and 10 cm from the positive end the wire in the two cases . The ratio of emf's is

A potentiometer wire is 100cm long and a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obtained at 50cm and 10cm from the positive end of the wire in two cases. The ratio of emf's is

A potentiometer wire is 100 cm long and a constant potential difference is maintained across it. Two cells of emfs epsi_(1) and epsi_(2) are connected in series first to support one another and then in opposition. The balance points were obtaind at 60 cm and 12 cm from the same end of the wire in the two cases. find the ratio of the emfs.

Using a potentiometer, balance points are obtained at 60 cm and 10 cm with two cells connected in series first to support one another and then in opposition respectively. Find the ratio of the emfs of the cells.

A potentiometer wire is 500 cm long and potential difference of 4 V is maintained between the ends of the wire. The e.m.f. of the cell which balances against the length of 135 cm of the wire is